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vika99vvv
@vika99vvv
July 2022
1
12
Report
Найдите массу 224 л пропана CH3-CH2-CH3 (н.у)
44г
100г
440г
4кг
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Answers & Comments
nezhdanof
Mолярная масса пропана M(C3H8)=12*3+1*8=44г/моль
Найдем количество пропана:
n(C3H8)=224/22.4=10моль
m(C3H8)=n*M=10*44=440г
Ответ: 440г
4 votes
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Answers & Comments
Найдем количество пропана:
n(C3H8)=224/22.4=10моль
m(C3H8)=n*M=10*44=440г
Ответ: 440г