Verified answer

Ответ:

дано

m(NH2-CH2-COOH) = 15 g

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m(H2NCH2CONHCH2COOH) - ?

NH2-CH2-COOH+NH2-CH2-COOH-->NH2-CH2-CO-NH-CH2-COOH+H2O

M(NH2CH2COOH)= 75 g/mol

n(NH2CH2COOH) = m/M = 15 / 75 = 0.2 mol

n(NH2CH2COOH) = n(NH2-CH2-CO-NH-CH2-COOH)

M(NH2-CH2-CO-NH-CH2-COOH) = 132 g/mol

m(NH2-CH2-CO-NH-CH2-COOH) = n*M= 0.2*132 = 26.4 g

ответ 26.4 г

Объяснение: