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sanche03
@sanche03
July 2022
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найдите массу глюкозы С6Н12О6, если количество= 0,1 моль.
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franken17
M(C6H12O6) = n(С6Н12О6) * М(С6Н12О6) = 0,1 * 180 = 18г
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