f(x)= 3x^5-5x^3+1 ; x € [-2;2]

f(-2) = -96 + 40 + 1 = -55

f(2) = 96 - 40 + 1 = 57

f'(x) = 15x^4 - 15x^2

f'(x) = 0

15x^4 - 15x^2 = 0

x^2 (x^2 - 1) = 0

x = 0 ; x = 1 ; x = -1

f(0) = 1

f(-1) = 3

f(1) = -1

min f(x) = f(-2) = -55

[-2;2]

max f(x) = f(2) = 57

[-2;2]

Ответ : -55; 57