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anastasia2108ny
@anastasia2108ny
July 2022
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Найдите наибольшее значение функции у=-х^2+2х+5
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DesmondHume
Y = -x^2 + 2x + 5
y' = -2x + 2
-2x + 2 = 0
-2x = -2
x = 1
Справа знак +
Слева -
Значит, x = 1 — точка максимума
ymax = -1^2 + 2 * 1 + 5 = 1 + 2 + 5 = 7
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anastasia2108ny
cgfcb,j ,jkmijt )
anastasia2108ny
спасибо большое )
Принцесуля31
Y = -x^2 + 2x + 5. y' = -2x + 2. -2x + 2 = 0-2x = -2. x = 1Значит, x = 1 — точка максимумаymax = -1^2 + 2 * 1 + 5 = 1 + 2 + 5 = 7
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Answers & Comments
y' = -2x + 2
-2x + 2 = 0
-2x = -2
x = 1
Справа знак +
Слева -
Значит, x = 1 — точка максимума
ymax = -1^2 + 2 * 1 + 5 = 1 + 2 + 5 = 7