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11x11manunited
@11x11manunited
August 2022
1
3
Report
Найдите наибольшее значение функции
y=
x 3
+3
x 2
−2
на отрезке
[
−3;
1 2
]
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Answers & Comments
Незнaйкa
У'=3x^2+6х=3x(х+2)
У'=0; 3x(x+2)=0
X=0;х=-2
У(-3)=(-3)^3+3•(-3)^2-2=-27+27-2=-2
У(-2)=(-2)^3+3•(-2)^2-2=-8+12-2=2
У(0)=-2
У(12)=12^3+3•12^2-2=1728+432-2=2158
Ymax=2158
4 votes
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Answers & Comments
У'=0; 3x(x+2)=0
X=0;х=-2
У(-3)=(-3)^3+3•(-3)^2-2=-27+27-2=-2
У(-2)=(-2)^3+3•(-2)^2-2=-8+12-2=2
У(0)=-2
У(12)=12^3+3•12^2-2=1728+432-2=2158
Ymax=2158