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photographer2000
@photographer2000
November 2021
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найдите наибольшее значение выражения √3 sin α + cos α
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армения20171
√3sina+cosa=2(√3/2sina+1/2*cosa)=
2(cosπ/6*sina+sinπ/6*cosa)=
2*sin(a+π/6)
sin(a+π/6)€[-1;1]
2*sin(a+π/6)€[-2;2]
ответ 2
5 votes
Thanks 9
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Answers & Comments
2(cosπ/6*sina+sinπ/6*cosa)=
2*sin(a+π/6)
sin(a+π/6)€[-1;1]
2*sin(a+π/6)€[-2;2]
ответ 2