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marat124
@marat124
July 2022
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Найдите наименьшее общее кратное чисел,разложив их на простые множители:
(1) 21и18 (2) 24и32 (3) 16и20 (4) 20и35 (5) 75и90 (6) 6и13
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Nastya171167
Verified answer
2
1 = 3*7
18 = 2*3*3
НОК(21, 18) = 2*3*3*7 = 126
24 = 2*2*2*3
32 = 2*2*2*2*2
НОК(24, 32) = 2*2*2*2*2*3 = 96
16 = 2*2*2*2
20 = 2*2*5
НОК(16, 20) = 2*2*2*2*5 = 80
20 = 2*2*5
35 = 5*7
НОК(20, 35) = 2*2*5*7 = 140
75 = 3*5*5
90 = 2*3*3*5
НОК(75, 90) = 2*3*3*5*5 = 450
6 = 2*3
13 - простое число.
НОК(6, 13) = 2*3*13 = 78
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Answers & Comments
Verified answer
21 = 3*718 = 2*3*3
НОК(21, 18) = 2*3*3*7 = 126
24 = 2*2*2*3
32 = 2*2*2*2*2
НОК(24, 32) = 2*2*2*2*2*3 = 96
16 = 2*2*2*2
20 = 2*2*5
НОК(16, 20) = 2*2*2*2*5 = 80
20 = 2*2*5
35 = 5*7
НОК(20, 35) = 2*2*5*7 = 140
75 = 3*5*5
90 = 2*3*3*5
НОК(75, 90) = 2*3*3*5*5 = 450
6 = 2*3
13 - простое число.
НОК(6, 13) = 2*3*13 = 78