kazimierz2015 [tex]f(x)=x^5-5x+8 \\ x\in [-2;3] \\ f'(x)=5x^4-5=0\iff 5(x^4-1)=0 \\ \iff (x-1)(x+1)(x^2+1)=0\iff x=-1;x=1 \\ f(-1)=-1+5+8=12 \\ f(1)=1-5+8=9-5=4 \\ f(-2)=-32+10+8=18-32=-14 \\ f(3)=243-15+8=251-15=236 \\ \underline{f(x)=-14};x=-2 \\ [/tex]