найдите наименьшее значение функции y=2xˆ2-8x+20 -12
y=2xˆ2-8x+20 -12
y=2xˆ2-8x+8
2x2 - 8x + 8 = 0Делим на 2:x2 - 4x + 4 = 0D = b2 - 4acD = 16 - 16 = 0
x = - b/2ax = 4/2 = 2x = 2
Хв= -в/2а=8/4=2Ув= 2*4-16+20-12=8-16+20-12=0
Ответ: 0
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y=2xˆ2-8x+20 -12
y=2xˆ2-8x+8
2x2 - 8x + 8 = 0
Делим на 2:
x2 - 4x + 4 = 0
D = b2 - 4ac
D = 16 - 16 = 0
x = - b/2a
x = 4/2 = 2
x = 2
Хв= -в/2а=8/4=2
Ув= 2*4-16+20-12=8-16+20-12=0
Ответ: 0