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ДжейнЛейн1
@ДжейнЛейн1
June 2022
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найдите наименьшее значение функции y(x)=3x^3-9 на отрезке [0;3]
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mikael2
y(x)=3x^3-9 [0;3]
y'(x)=9x² x=0 → y'(x)=0
y(0)=-9 y(3)=3*27-9>0
ymin=-9
2 votes
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Answers & Comments
y'(x)=9x² x=0 → y'(x)=0
y(0)=-9 y(3)=3*27-9>0
ymin=-9