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July 2022
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Найдите наименьший положительный корень уравнения 4cosπx - sin2πx=0
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mikael2
4cosπx-sin2πx=0 4сosπx-2sinπxcosπx=0 2cosπx(2-sinπx)=0
cosπx=0 πx=π/2+πn x=1/2+n n∈Z
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4cosπx-sin2πx=0 4сosπx-2sinπxcosπx=0 2cosπx(2-sinπx)=0
cosπx=0 πx=π/2+πn x=1/2+n n∈Z