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Yaroslav1Slavyanin
@Yaroslav1Slavyanin
July 2022
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Найдите наименьший положительный корень уравнения cosx*cos2x=cos3x
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lokki11
Будет
(cos3x-cosx)/2 = cos3x
cos3x+cosx = 0
2cos2x*cosx = 0
cos2x*cosx = 0
cos2x = 0 или cosx = 0
2x = П/2+Пn, x = П/4 + Пn/2
x = П/2+Пn
При n = 0 наименьший положительный корень уравнения x = П/4
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Answers & Comments
(cos3x-cosx)/2 = cos3x
cos3x+cosx = 0
2cos2x*cosx = 0
cos2x*cosx = 0
cos2x = 0 или cosx = 0
2x = П/2+Пn, x = П/4 + Пn/2
x = П/2+Пn
При n = 0 наименьший положительный корень уравнения x = П/4