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@sddsgfmiuaewlkjfvhu
August 2022
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найдите нули функции (если они существуют): a)y=-0,2x+46; б)y=x(x+1) (x-2)
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arin567
А) -0,2х+46=0
-0,2х=-46
х=-46:(-0,2)
х=230
б) х(х+1)(х-2)=0
х=0 х+1 = 0 х-2=0
х=-1 х=2
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Answers & Comments
-0,2х=-46
х=-46:(-0,2)
х=230
б) х(х+1)(х-2)=0
х=0 х+1 = 0 х-2=0
х=-1 х=2