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July 2022
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НАЙДИТЕ НУЛИ ФУНКЦИИ f(x)=-2x^2+5x-2
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belozerova1955
Н.ф. -2х²+5х-2=0
2х²-5х+2=0
D=b²-4ac = (-5)² -4·2·2=25-16=9 >0, два корня.
х₁=(5+√9) : 4= (5+3) : 4 = 2
х₂=(5-3) : 4= 2:4=0,5
Ответ: 2; 0,5
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дану2015
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Answers & Comments
2х²-5х+2=0
D=b²-4ac = (-5)² -4·2·2=25-16=9 >0, два корня.
х₁=(5+√9) : 4= (5+3) : 4 = 2
х₂=(5-3) : 4= 2:4=0,5
Ответ: 2; 0,5