Найдите нули функции: y=x³+2x²-x-2; y=x³-x²-9x+9.
Подробно.
x^3+2x^2-x-2=0
x^2(x+2)-(x+2)=0
(x+2)(x^2-1)=0
(x+2)(x-1)(x+1)=0
x=-2, x=1, x=-1
(-2;0) (1;0) (-1;0)
x^3-x^2-9x+9=0
x^2(x-1)-9(x-1)=0
(x-1)(x-3)(x+3)=0
x=1 x=3 x=-3
(1;0) (3;0) (-3;0)
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Verified answer
x^3+2x^2-x-2=0
x^2(x+2)-(x+2)=0
(x+2)(x^2-1)=0
(x+2)(x-1)(x+1)=0
x=-2, x=1, x=-1
(-2;0) (1;0) (-1;0)
x^3-x^2-9x+9=0
x^2(x-1)-9(x-1)=0
(x-1)(x-3)(x+3)=0
x=1 x=3 x=-3
(1;0) (3;0) (-3;0)