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NastyaLittle
@NastyaLittle
August 2022
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Найдите нули функции:
y=x^3-x^2+x-1
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infor5
Ответ 1
y=x^2(x-1)+(x-1)=(x-1)(x^2+1)
y=0 x-1=0 x=1
x^2+1=0 (это уравнение не имеет решения)
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Answers & Comments
y=x^2(x-1)+(x-1)=(x-1)(x^2+1)
y=0 x-1=0 x=1
x^2+1=0 (это уравнение не имеет решения)