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Alia0489
@Alia0489
July 2022
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найдите оба корня уравнения 7(х^2)=х+2006
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nana1179
7х²-х-2006=0
D=1-4×7×(-2006)=√56 169 = 237
х1 = 1+237/2×7 = 238/14 = 17
х2 = 1-237/2×7 = -236/14 = -118/7
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Answers & Comments
D=1-4×7×(-2006)=√56 169 = 237
х1 = 1+237/2×7 = 238/14 = 17
х2 = 1-237/2×7 = -236/14 = -118/7