n(C6H5NH2) = 98/93 = 1,054 моль.
4С6H5NH2 + 31O2 = 24CO2 + 14H2O + 2N2
4 31
1,054 х
х = 1,054*31/4 = 8,1658 моль (О2)
V(O2) = 8.1658*22.4 = 182.7 л
V(возд) = 182,7/0,21 = 871,3 л.
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Answers & Comments
n(C6H5NH2) = 98/93 = 1,054 моль.
4С6H5NH2 + 31O2 = 24CO2 + 14H2O + 2N2
4 31
1,054 х
х = 1,054*31/4 = 8,1658 моль (О2)
V(O2) = 8.1658*22.4 = 182.7 л
V(возд) = 182,7/0,21 = 871,3 л.