Ответ:
Объяснение: Б-бескон-ть
D(y)= (-Б;+Б)
-1<=cos2x<=1
-3<=3cos2x<=3
-3-1<=3cos2x-1<=3-1
-4<=3cos2x-1<=2
E(y)=[-4;2]
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Ответ:
Объяснение: Б-бескон-ть
D(y)= (-Б;+Б)
-1<=cos2x<=1
-3<=3cos2x<=3
-3-1<=3cos2x-1<=3-1
-4<=3cos2x-1<=2
E(y)=[-4;2]