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MonSlon
@MonSlon
August 2022
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Найдите область определения:
y=arcsin(x²+x-1)
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mikael2
-1≤x²+x-1≤1
x²+x-2≤0 (x+2)(x-1)≤0
///////////////////////////////////
-------------------- -2--------------------------- 1-----------------------
- +
x²+x≥0 x(x+1)≥0
/////////////////////////////////////////////// ///////////////////////////////////////
------------------------------------ -1------0-----------------------------
+ - +
x∈[-2;-1]∪[0;1]
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Answers & Comments
x²+x-2≤0 (x+2)(x-1)≤0
///////////////////////////////////
-------------------- -2--------------------------- 1-----------------------
- +
x²+x≥0 x(x+1)≥0
/////////////////////////////////////////////// ///////////////////////////////////////
------------------------------------ -1------0-----------------------------
+ - +
x∈[-2;-1]∪[0;1]