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mashka44
@mashka44
September 2021
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beton7stalker
D(y):
√(4x-x²)≥0
4x-x²≥0
x(4-x)≥ 0
D(y): xє(-∞;0)вместе спромежутком (4;+∞)
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Answers & Comments
√(4x-x²)≥0
4x-x²≥0
x(4-x)≥ 0
D(y): xє(-∞;0)вместе спромежутком (4;+∞)