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iskakova2000
@iskakova2000
August 2022
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Найдите область значений функции y=1+√3sinx
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Verified answer
Найдите область значений функции y=
1+√3sinx
-1≤sinx≤1 ⇒ 1-√3≤(1+√3sinx)≤1+√3
1-√3≤ y ≤1+√3
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Verified answer
Найдите область значений функции y=1+√3sinx-1≤sinx≤1 ⇒ 1-√3≤(1+√3sinx)≤1+√3
1-√3≤ y ≤1+√3