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Susake
@Susake
July 2022
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найдите область значения функции y=x^2-2x-8, где x€[-1;3]
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hlopushinairina
Y=x²-2x-8;x∈[-1;3].
x=-1;⇒y=1+2-8=-5;
x=3;⇒y=9-6-8=-5;
y₀=-(b²-4ac)/4a=-(4-4·1·(-8))/4·1=-(4+32)/4=-36/4=-9;
x∈[-1;3]⇒y∈[-5;-9];
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Answers & Comments
x=-1;⇒y=1+2-8=-5;
x=3;⇒y=9-6-8=-5;
y₀=-(b²-4ac)/4a=-(4-4·1·(-8))/4·1=-(4+32)/4=-36/4=-9;
x∈[-1;3]⇒y∈[-5;-9];