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Voiren
@Voiren
December 2021
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Найдите периметр ΔABC, если точка А(7;1;-5) точка В(4;-3;-4) точка С(1;3;-2;)
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А(7;1;-5) В(4;-3;-4) С(1;3;-2)
= (4 - 7)
² + (-3 - 1)² +(-4 + 5)² = 9 + 16 + 1 = 26
AB = √26
= (1 - 7)² + (3 - 1)² + (-2 + 5)² = 36 + 4 + 9 = 49
AC = √49 = 7
= (4 - 1)² + (-3 - 3)² + (-4 + 2)² = 9 + 36 + 4 = 49
CB = √49 = 7
= √26 + 7 + 7 = 14 + √26
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Answers & Comments
Verified answer
А(7;1;-5) В(4;-3;-4) С(1;3;-2)= (4 - 7)² + (-3 - 1)² +(-4 + 5)² = 9 + 16 + 1 = 26
AB = √26
= (1 - 7)² + (3 - 1)² + (-2 + 5)² = 36 + 4 + 9 = 49
AC = √49 = 7
= (4 - 1)² + (-3 - 3)² + (-4 + 2)² = 9 + 36 + 4 = 49
CB = √49 = 7