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yfhrjnbr0
@yfhrjnbr0
July 2022
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Найдите первообразную функции f(x), график которой проходит через точку А, если f(x)=3х^2-6, A(1; 4).
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sharadi
Verified answer
F(x) = 3x³/3 - 6x = x³ - 6x + C , A(1, 4)
4 = 1³ - 6*1 + C
C = 9
Ответ: F(x) = x³ - 6x +9
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Answers & Comments
Verified answer
F(x) = 3x³/3 - 6x = x³ - 6x + C , A(1, 4)4 = 1³ - 6*1 + C
C = 9
Ответ: F(x) = x³ - 6x +9