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dima20061998
@dima20061998
July 2022
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Найдите первый член арифметической прогрессии, если :
1) a5 = 43, a9 = 21
2) a7 = 36, a15 = 64
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Snovvflake
Verified answer
А9=а5+4d
4d=21-43
4d=-22
d=-5,5
a1=a5-4d
a1=43+22
a1=65
Ответ: 65.
а7=36
а15=64
а15=а7+8d
64=36+8
8d=64-36
8d=28
d=3,5
a7=a1+6d
36=a1+21
a1=36-21=15
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Answers & Comments
Verified answer
А9=а5+4d4d=21-43
4d=-22
d=-5,5
a1=a5-4d
a1=43+22
a1=65
Ответ: 65.
а7=36
а15=64
а15=а7+8d
64=36+8
8d=64-36
8d=28
d=3,5
a7=a1+6d
36=a1+21
a1=36-21=15