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zog1502271
@zog1502271
July 2022
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найдите площадь треугольника АБС, ЕСЛИ ВС=3см, АВ=18√2см, уголВ= 45°
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Prozorova1998
S=1/2*AВ*ВС*sin45
S=(0.5*18√2*3)/√2=27
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S=(0.5*18√2*3)/√2=27