Ответ:
1−cos2x−cos2x=0,51−2cos2x=0,52cos2x=1−0,52cos2x=0,5cos2x=0,25cosx=0,25=∣0,5∣=±0,5=±21x=±3π+2πk
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Ответ:
1−cos2x−cos2x=0,51−2cos2x=0,52cos2x=1−0,52cos2x=0,5cos2x=0,25cosx=0,25=∣0,5∣=±0,5=±21x=±3π+2πk