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Bliznyashki
@Bliznyashki
July 2022
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Найдите приращение функции f(x) в точке х0:
1)f(x)= 1+2x, x0= 4, delta x= 0,01
2)f(x)= -5х+1,6, х0= -5, delta х= -0,1
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mikael2
Verified answer
1/ x0+deltax=x1=4.01 f(x0)=1+2*4=9
f(x1)=1+2*4.01=1+8.02=9.02 delta f(x) =9.02-9=0.2
2/ f(x)=-5x+1.6 f(x0)=-5(-5)+1.6=25+1.6=26.6
x1=-5-0.1=-5.1 f(-5.1)=-0.55(-5.1)+1.6=27.1
delta f(x)=27.1-26.6=0.5
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Verified answer
1/ x0+deltax=x1=4.01 f(x0)=1+2*4=9f(x1)=1+2*4.01=1+8.02=9.02 delta f(x) =9.02-9=0.2
2/ f(x)=-5x+1.6 f(x0)=-5(-5)+1.6=25+1.6=26.6
x1=-5-0.1=-5.1 f(-5.1)=-0.55(-5.1)+1.6=27.1
delta f(x)=27.1-26.6=0.5