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ЭHэнни
@ЭHэнни
August 2022
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найдите произведение корней уравнения lg2x+lgx-12=0
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MizoriesKun
Lg²x+lgx-12=0 замена lgx=а
а²+а-12=0
D=1+48-49 √D=7
a₁=(-1+7)/2=3 lgx=3 x₁=1000
a₂=(-1-7)/2=-4 lgx= -4 x₂= 1/10000
x₁*x₂=1000 *(1/10000)=1/10=0,1
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Answers & Comments
а²+а-12=0
D=1+48-49 √D=7
a₁=(-1+7)/2=3 lgx=3 x₁=1000
a₂=(-1-7)/2=-4 lgx= -4 x₂= 1/10000
x₁*x₂=1000 *(1/10000)=1/10=0,1