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afinka16
@afinka16
November 2021
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найдите произведение многочлена и одночлена:4 (b-3); b(3+2b); 0,1y (5y+8); -0,6y (1,5y-3)
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koba80
4(b-3)=4b-12; b(3+2b)=3b+2b^2;
0,1y(5y+8)=1y/10(5y+8)=y^2/2+4y/5=0,5y^2+0,8y
-0,6y(1,5y-3) = -6y/10(3y/2-3) = -18y^2/20 + 18y/10=-0,9y^2+1,8y
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акелла13
а что значит /
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Answers & Comments
0,1y(5y+8)=1y/10(5y+8)=y^2/2+4y/5=0,5y^2+0,8y
-0,6y(1,5y-3) = -6y/10(3y/2-3) = -18y^2/20 + 18y/10=-0,9y^2+1,8y