y' = (ln(x^2 + x))' = (x^2 + x)'/(x^2 + x) = (2x + 1)/(x^2 + x)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
y' = (ln(x^2 + x))' = (x^2 + x)'/(x^2 + x) = (2x + 1)/(x^2 + x)