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neznayka144
@neznayka144
August 2022
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найдите производную функции
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Indentuum
Y = e^x * cosx
(u*v)’ = u*v’ + u’*v
y’ = e^x*(cosx)’ + (e^x)’*cosx = e^x*(cosx - sinx)
y’(0) = 1*(1-0)=1
1 votes
Thanks 1
ФунтикКрасавчик
можно вопрос? куда делали второй e^x?
Indentuum
Вынесли за скобку
Indentuum
(e^x)’=e^x*ln(e)=e^x
Indentuum
Если вы про это
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Answers & Comments
(u*v)’ = u*v’ + u’*v
y’ = e^x*(cosx)’ + (e^x)’*cosx = e^x*(cosx - sinx)
y’(0) = 1*(1-0)=1