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Alex364
@Alex364
August 2022
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Найдите производную функцию y=sin(3 степень)*(2x-7) в точке x0=3.
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tseluyko58
Verified answer
Y`=3*2*sin²(2x-7)cos(2x-7)=6sin²(2x-7)cos(2x-7)
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tseluyko58
y`(3)=6sin^2 1cos1
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Verified answer
Y`=3*2*sin²(2x-7)cos(2x-7)=6sin²(2x-7)cos(2x-7)