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doterovich97
@doterovich97
July 2022
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Найдите производную подробно пожалуйста)
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армения20171
у = аrctg⁴( 2x )
y' = 4 × arctg³( 2x ) × ( arctg ( 2x ) )' = 4arctg³ ( 2x ) × 2 /( 1 + 4x² ) = 8arctg³( 2x ) / ( 1 + 4x² )
ОТВЕТ: 8arctg³( 2x ) / ( 1 + 4x² )
1 votes
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Mihail001192
Verified answer
Y'=(arctg⁴2x)'=4•arctg³(2x)•(arctg2x)'=
4•arctg³(2x)•1/(1+4x²)•(2x)'=
8arctg³(2x)/(1+4x²)
1 votes
Thanks 0
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Answers & Comments
у = аrctg⁴( 2x )
y' = 4 × arctg³( 2x ) × ( arctg ( 2x ) )' = 4arctg³ ( 2x ) × 2 /( 1 + 4x² ) = 8arctg³( 2x ) / ( 1 + 4x² )
ОТВЕТ: 8arctg³( 2x ) / ( 1 + 4x² )
Verified answer
Y'=(arctg⁴2x)'=4•arctg³(2x)•(arctg2x)'=4•arctg³(2x)•1/(1+4x²)•(2x)'=
8arctg³(2x)/(1+4x²)