f(x) = x³ - 3x² + 4
f'(x) = 3x² - 6x
f'(x) = 0
3x² - 6x = 0
3x(x - 2) = 0
x = 0 или x = 2
-∞__+__( 0 )_-_( 2 )__+__+∞
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
f(x) = x³ - 3x² + 4
f'(x) = 3x² - 6x
f'(x) = 0
3x² - 6x = 0
3x(x - 2) = 0
x = 0 или x = 2
-∞__+__( 0 )_-_( 2 )__+__+∞
f'(x) > 0 при x ∈ (-∞; 0) и x ∈ (2; +∞)
f'(x) < 0 при x ∈ (0; 2)