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irinakotik17
@irinakotik17
August 2022
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Найдите q если х1=1, х2=2 - нули квадратичной функции y=x^2+gx+q
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crafting2000203
По теореме Виета:
x1+x2 = -g/a
x1*x2 = q/a
Следовательно,по теореме Виета:
q=1*2=2
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irinakotik17
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Answers & Comments
x1+x2 = -g/a
x1*x2 = q/a
Следовательно,по теореме Виета:
q=1*2=2