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irina2543
@irina2543
July 2022
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Найдите р(х)+р1(х)-р2(х),если р1(х)+х-8;р2(х)+(3 в кубе)+х-4
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Юленька194
Verified answer
Р(х)=р1(х)-р2(х)= (х-8)- (3x³
+х-4
)= x-8-3x³-x+4= -x³+x-x-8+4=-3x³-4
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Verified answer
Р(х)=р1(х)-р2(х)= (х-8)- (3x³+х-4)= x-8-3x³-x+4= -x³+x-x-8+4=-3x³-4