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Annette37
@Annette37
June 2022
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Найдите самое большое и самое маленькое значение
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m11m
Verified answer
Y=ˣ²⁺⁸/ₓ₋₁
y'=[2x(x-1)-(x²+8)]/(x-1)² =(2x²-2x-x²-8)/(x-1)²=(x²-2x-8)/(x-1)²
(x²-2x-8)/(x-1)² =0
x≠1
x²-2x-8=0
По т.Виета:
x₁=4∉[-3; 0]
x₂= -2∈[-3; 0]
При x= -3
y=[(-3)²+8]/(-3-1)= - 17/4= -4.25
При x= -2
y=[(-2)²+8]/(-2-1)= -12/3= -4 - наибольшее значение
При x=0
y=[0²+8]/(0-1)= -8 - наименьшее значение
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Answers & Comments
Verified answer
Y=ˣ²⁺⁸/ₓ₋₁y'=[2x(x-1)-(x²+8)]/(x-1)² =(2x²-2x-x²-8)/(x-1)²=(x²-2x-8)/(x-1)²
(x²-2x-8)/(x-1)² =0
x≠1
x²-2x-8=0
По т.Виета:
x₁=4∉[-3; 0]
x₂= -2∈[-3; 0]
При x= -3
y=[(-3)²+8]/(-3-1)= - 17/4= -4.25
При x= -2
y=[(-2)²+8]/(-2-1)= -12/3= -4 - наибольшее значение
При x=0
y=[0²+8]/(0-1)= -8 - наименьшее значение