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germanb99
@germanb99
July 2022
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найдите сумму 16 первых членов последовательности (b7),заданной формулой b7=3n-1
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Д1Е1М1О1Н
B1=3*1-1=2
b2=3*2-1=5
d=b2-b1
d=5-2=3
b16=b1+d(n-1)
b16=2+45=47
S16=((b1+b16)16)/2
S16=(2+47)8=392
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germanb99
найдите 21член арифметической прогрессии -21,-18,-15
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Answers & Comments
b2=3*2-1=5
d=b2-b1
d=5-2=3
b16=b1+d(n-1)
b16=2+45=47
S16=((b1+b16)16)/2
S16=(2+47)8=392