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yanaaleynik
@yanaaleynik
October 2021
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Найдите сумму двадцати двух первых членов арифметической прогрессии:3;11;..
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армения20171
3;11;19;
а1=3;d=8
a22=a1+21*d=3+21*8=171
S=(a1+a22)/2 *22=(3+171)*11=174*11=
=1914
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Answers & Comments
а1=3;d=8
a22=a1+21*d=3+21*8=171
S=(a1+a22)/2 *22=(3+171)*11=174*11=
=1914