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Viktoria9816
@Viktoria9816
August 2022
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Найдите сумму корней уравнением (x-4)^2=4-x
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ЛёляВладимировна
(x-4)^2=4-x
x^2-8x+16+x-4=0
x^2-7x+12=0
D=49-48=1
x1=7+1/2=4; x2=7-1/2=3
x1+x2=4+3=7.
Ответ 7 :)
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yanasevastyano
X^2-7x+12=0
x1=-3
x2=-4
-3+-4=-7
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Answers & Comments
x^2-8x+16+x-4=0
x^2-7x+12=0
D=49-48=1
x1=7+1/2=4; x2=7-1/2=3
x1+x2=4+3=7.
Ответ 7 :)
x1=-3
x2=-4
-3+-4=-7