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princess119991
@princess119991
July 2022
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Найдите сумму корней уравнения:(x в квадрате-7x)+x-7=0
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svetazuna
(х² - 7х) + х - 7 = 0,
х² - 6х - 7 = 0,
Д = (-6)² - 4*1*(-7) = 36 + 28 = 64,
х1 =
(6 + 8)/2*1 = 14/2 =
7,
х2 =
(6 - 8)/2*1 = -2/2 = -1,
х1 + х2 =
7 + (-1) = 7 - 1
= 6
1 votes
Thanks 1
армения20171
(х^2-7х)+х-7=0
х^2-6х-7=0
Д=6^2+4•7=36+28=64>0
х1=(6+√64)/2=14/2=7
х2=(6-8)/2= -1
х1+х2=7+(-1)=6
можно т.Виеета
х1+х2=6
1 votes
Thanks 1
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Answers & Comments
х² - 6х - 7 = 0,
Д = (-6)² - 4*1*(-7) = 36 + 28 = 64,
х1 = (6 + 8)/2*1 = 14/2 = 7,
х2 = (6 - 8)/2*1 = -2/2 = -1,
х1 + х2 = 7 + (-1) = 7 - 1 = 6
х^2-6х-7=0
Д=6^2+4•7=36+28=64>0
х1=(6+√64)/2=14/2=7
х2=(6-8)/2= -1
х1+х2=7+(-1)=6
можно т.Виеета
х1+х2=6