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kalininayulia98
@kalininayulia98
August 2022
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найдите сумму первых 30-ти членов арифметической прогрессии, в которой а(9)=-11 , а(19)=19
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EricWay
D=a(m)-a(n)/m-n=19-(-11)/19-9=3
a1=a(n)-d(n-1)=19-3*18=-35
S(30)=2a1*d(n-1)/2*n=2*(-35)*3(30-1)/2*30=255
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a1=a(n)-d(n-1)=19-3*18=-35
S(30)=2a1*d(n-1)/2*n=2*(-35)*3(30-1)/2*30=255