Найдите сумму: первых четырех членов прогрессии: √6,3√ 2,3√ 6.... (геометрическая прогрессия)
b1=V6 b2=V18 q=b2/b1=V3
S4=b1(q^4-1)/q-1={V6(9-1)}/(v3 -1)= 8V6(V3+1)/{(V3-1)(V3+1)=8V6(V3+1)/2=4V6(V3+1)=
=4V18-4V6=12V2-4V6
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b1=V6 b2=V18 q=b2/b1=V3
S4=b1(q^4-1)/q-1={V6(9-1)}/(v3 -1)= 8V6(V3+1)/{(V3-1)(V3+1)=8V6(V3+1)/2=4V6(V3+1)=
=4V18-4V6=12V2-4V6