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ulpanakhmetova
@ulpanakhmetova
July 2022
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найдите сумму первых n членов геометрической прогрессии если b7=16\9 . q=2\3 . n=7
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sedinalana
Verified answer
B1=b7/q^6=16/9:64/729=16/9*729/64=81/4
S7=b1*(1-q^7)/(1-q)=81/4*(1-128/2187):(1-2/3)=
=81/4*2059/2187*3=2059/36=57 7/36
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Verified answer
B1=b7/q^6=16/9:64/729=16/9*729/64=81/4S7=b1*(1-q^7)/(1-q)=81/4*(1-128/2187):(1-2/3)=
=81/4*2059/2187*3=2059/36=57 7/36