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AzIzA26022001
@AzIzA26022001
August 2022
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Найдите сумму пяти первых членов геометрической прогрессии (хп), если х1=0,48, х2=0,32.
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sedinalana
Verified answer
Q=x2/x1=32/48=2/3
S5=x1*(1-q^5)/(1-q)
S5=0,32*(1-32/243):(1-2/3)=0,32*211/243*3=1688/2025
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AzIzA26022001
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Verified answer
Q=x2/x1=32/48=2/3S5=x1*(1-q^5)/(1-q)
S5=0,32*(1-32/243):(1-2/3)=0,32*211/243*3=1688/2025