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Assassin1486
@Assassin1486
June 2022
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Найдите сумму шести первых членов геометрической прогрессии (Xn), если X1 = 0,45 ; X2 = 0,15.
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lerarhipova189
Q= x2/x1 = 0,15/0,45 = 0,3
Sn = b1(qⁿ - 1)/(q-1)
S10 = 0,45((0.3)^6- 1)/(0.3 - 1)
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Answers & Comments
Sn = b1(qⁿ - 1)/(q-1)
S10 = 0,45((0.3)^6- 1)/(0.3 - 1)