сумма ста членов S120=(b1+b120)*120/2
b1=3*1-2=1
b120=3*120-2=358
S120=(1+358)*120/2= 21540
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сумма ста членов S120=(b1+b120)*120/2
b1=3*1-2=1
b120=3*120-2=358
S120=(1+358)*120/2= 21540